1. Raise up right hand's middle finger
2. Flip all your 10 fingers up side down
3. The 7 and 2 are the numerator at the upper positor
4. Put the rate of return at the denominator
5. Division gives the number of year to get back the initial captial
grep -v) However I want to know if it is possible using regular expressions to match lines which does not contain a specific word, say hede?Hoho
Hihi
Haha
hede
# grep "Regex for do not contain hede" InputHoho
Hihi
Haha
Note that the solution to does not start with “hede”:
^(?!hede).*$
is generally much more efficient than the solution to does not contain “hede”:
^((?!hede).)*$
The former checks for “hede” only at the input string’s first position, rather than at every position.
How to remove new line in Notepad++?
You need something like a regular expression.
You have to be in Extended mode
If you want all the lines to end up on a single line use \r\n. If you want to simply remove emptylines, use \n\r as @Link originally suggested.
Replace either expression with nothing.
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| <?xml version="1.0" encoding="utf-8" ?><pets> <cat color="black" weight="10"> <price>100</price> <desc>this is a black cat</desc> </cat> <cat color="white" weight="9"> <price>80</price> <desc>this is a white cat</desc> </cat> <cat color="yellow" weight="15"> <price>80</price> <desc>this is a yellow cat</desc> </cat> <dog color="black" weight="10"> <price>100</price> <desc>this is a black dog</desc> </dog> <dog color="white" weight="9"> <price>80</price> <desc>this is a white dog</desc> </dog> <dog color="yellow" weight="15"> <price>80</price> <desc>this is a yellow dog</desc> </dog></pets> |
符号
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说明
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示例
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示例说明
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/
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表示从根节点开始选择
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/pets
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选择根节点pets
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表示节点和子节点之间的间隔符
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/pets/dog
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选择pets节点下的dog节点
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//xx
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表示从整个xml文档中查找,而不考虑当前节点位置
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//price
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选择文档中所有的price节点
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.
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单个英文半角句点表示选择当前节点
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/pets/.
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选择pets节点
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..
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双点,表示选择父节点
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/pets/dog[0]/..
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表示pets节点,也就是第一个dog节点的父节点
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@xx
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表示选择属性
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//dog/@color
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表示选择所有dog节点的color属性集合
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[…]
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中括号表示选择条件,括号内为条件
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//dog[@color=’white’]
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所有color为white的dog节点
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//dog[/price<100]
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所有price字节点值小于100的dog节点
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中括号内数字为节点索引,类似c#等语言中的数组,数组下标是从1开始的
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//dog[1]
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第1个dog节点
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//dog[last()]
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最后一个dog节点,last()是xPath内置函数
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单竖杠表示合并节点结合
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//dog[@color=’white’] | //cat[@color=’white’]
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color属性为white的dog节点和color属性为white的cat节点
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*
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星号表示任何名字的节点或者属性
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//dog/*
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表示dog节点的所有子节点
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//dog/@*
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表示dog节点的所有属性节点
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关键字
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说明
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示例
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示例说明
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ancestor
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当前节点的父祖节点
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ancestor::pig
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当前节点的祖先节点中的pig节点
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ancestor-or-self
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当前节点以及其父祖节点
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ancestor::pig
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attribute
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当前节点的所有属性
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attribute::weight
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相当于@weight,attribute::和@是等价的
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child
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当前节点的所有字节点
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child::*[name()!=’price’]
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选择名字不是price的子节点
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descendant
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子孙节点
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descendant::*[@*]
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有属性的子孙节点
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descendant-or-self
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子孙节点以及当前节点
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descendant-or-self::*
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following
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Xml文档中当前节点之后的所有节点
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following::*
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following-sibling
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当前节点的同父弟弟节点
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following-sibling::
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preceding
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Xml文档中当前节点之前的所有节点
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preceding::*
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namespace
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选取当前节点的所有命名空间节点
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namespace::*
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parent
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当前节点的父节点
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parent::
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相当于双点..
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preceding-sibling
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当前节点之后的同父兄节点
|
preceding-sibling::*
| |
self
|
当前节点
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self::*
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相当于单点.
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| using System;using System.Collections.Generic;using System.Linq;using System.Text;using System.Xml.XPath;using System.Xml;namespace UseXPathDotNet{ class Program { static void Main(string[] args) { UseXPathWithXPathDocument(); UseXPathWithXmlDocument(); Console.Read(); } static void UseXPathWithXmlDocument() { XmlDocument doc = new XmlDocument(); //使用xPath选择需要的节点 XmlNodeList nodes = doc.SelectNodes("/rss/channel/item[position()<=10]"); foreach (XmlNode item in nodes) { string title = item.SelectSingleNode("title").InnerText; string url = item.SelectSingleNode("link").InnerText; Console.WriteLine("{0} = {1}", title, url); } } static void UseXPathWithXPathDocument() { XPathNavigator xPathNav = doc.CreateNavigator(); //使用xPath取rss中最新的10条随笔 XPathNodeIterator nodeIterator = xPathNav.Select("/rss/channel/item[position()<=10]"); while (nodeIterator.MoveNext()) { XPathNavigator itemNav = nodeIterator.Current; string title = itemNav.SelectSingleNode("title").Value; string url = itemNav.SelectSingleNode("link").Value; Console.WriteLine("{0} = {1}",title,url); } } }} |
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| using System;using System.Collections.Generic;using System.Linq;using System.Text;using System.IO;using System.Xml;namespace UseXPath1{ class Program { static void Main(string[] args) { string xml = @"<?xml version=""1.0"" encoding=""utf-8"" ?><pets> <cat color=""black"" weight=""10"" count=""4""> <price>100</price> <desc>this is a black cat</desc> </cat> <cat color=""white"" weight=""9"" count=""5""> <price>80</price> <desc>this is a white cat</desc> </cat> <cat color=""yellow"" weight=""15"" count=""1""> <price>110</price> <desc>this is a yellow cat</desc> </cat> <dog color=""black"" weight=""10"" count=""7""> <price>114</price> <desc>this is a black dog</desc> </dog> <dog color=""white"" weight=""9"" count=""4""> <price>80</price> <desc>this is a white dog</desc> </dog> <dog color=""yellow"" weight=""15"" count=""15""> <price>80</price> <desc>this is a yellow dog</desc> </dog> <pig color=""white"" weight=""100"" count=""2""> <price>8000</price> <desc>this is a white pig</desc> </pig></pets>"; using (StringReader rdr = new StringReader(xml)) { XmlDocument doc = new XmlDocument(); doc.Load(rdr); //取所有pets节点下的dog字节点 XmlNodeList nodeListAllDog = doc.SelectNodes("/pets/dog"); //所有的price节点 XmlNodeList allPriceNodes = doc.SelectNodes("//price"); //取最后一个price节点 XmlNode lastPriceNode = doc.SelectSingleNode("//price[last()]"); //用双点号取price节点的父节点 XmlNode lastPriceParentNode = lastPriceNode.SelectSingleNode(".."); //选择weight*count=40的所有动物,使用通配符* XmlNodeList nodeList = doc.SelectNodes("/pets/*[@weight*@count=40]"); //选择除了pig之外的所有动物,使用name()函数返回节点名字 XmlNodeList animalsExceptPigNodes = doc.SelectNodes("/pets/*[name() != 'pig']"); //选择价格大于100而不是pig的动物 XmlNodeList priceGreaterThan100s = doc.SelectNodes("/pets/*[price div @weight >10 and name() != 'pig']"); foreach (XmlNode item in priceGreaterThan100s) { Console.WriteLine(item.OuterXml); } //选择第二个dog节点 XmlNode theSecondDogNode = doc.SelectSingleNode("//dog[position() = 2]"); //使用xpath ,axes 的 parent 取父节点 XmlNode parentNode = theSecondDogNode.SelectSingleNode("parent::*"); //使用xPath选择第二个dog节点前面的所有dog节点 XmlNodeList dogPresibling = theSecondDogNode.SelectNodes("preceding::dog"); //取文档的所有子孙节点price XmlNodeList childrenNodes = doc.SelectNodes("descendant::price"); } Console.Read(); } }} |
Reference https://blog.csdn.net/jiuhebaobao/article/details/137256664